[Coco] Sharing a value with the calling routine in Basic09

[Jeff Teunissen]

It sounds like you're trying to call something in _another process_
and get the value back out. Is that right?

On Sat, Aug 15, 2020 at 4:19 PM <coco at jechar.ca> wrote:
>
> I don't think what you are saying is correct because
> say my programs were called x and y
>
> in x I set p=SOME-VALUE
> then I print p and get
> SOME-VALUE
> then I call y passing p to y
> then I  set p=some-OTHER-value
> then I print p and get
> some-OTHER-value
> but when back in the calling program x
> when I print p and get
> SOME-VALUE
> so basic09 did not remember what module y did.
>
>
>
> On 2020-08-15 15:49, Wayne Campbell wrote:
> > Pass by reference is the default. This means that just passing the
> > variable
> > name is enough. If you update that variable and the procedure you
> > called
> > the variable in the procedure that called it will reflect that change.
> > To
> > pass by value, you use the variable name plus zero in the parameter
> > list.
> >
> > Example:
> >
> > RUN myProc(myVar+0)
> >
> > Passes myVar by it's value.
> >
> > RUN myProc(myVar)
> >
> > Passes myVar by reference.
> >
> >
> > On Sat, Aug 15, 2020, 11:21 AM <coco at jechar.ca> wrote:
> >
> >>
> >> On 2020-08-15 14:17, coco at jechar.ca wrote:
> >> > Would like to know if there is a standard way to pass back the
> >> > value from a called routine to the caller. Cannot use GOSUB the
> >> > routines need to be separate modules although a merged module file
> >> > could be created by OS9 afterwards to make sure that if one module
> >> > is loaded the other is too.
> >> >
> >> > I have an Idea involving ADDR PEEK and POKE of course if I am wrong
> >> > this could go very wrong.
> >> >
> >> > Charlie
> >>
> >> PS: I think what I am trying to do is called pass by reference
> >> in C++
> >>
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>
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