[Coco] [OT] 4Q

[John W. Linville]

On Thu, Sep 24, 2015 at 10:18:24PM -0400, Barry Nelson wrote:
> First, I believe this should be in a new thread.

Not a new one, just a different one -- I'm not sure how you managed
that?!?!  It looks like you copied the email by Camillus, then replied
to the 512k upgrade thread...?  Either that, or your MUA (i.e. email
client) is really confused...

> Second, as American, I would just like to note that 2Q^2 and 4Q are only equal for Q=2 or Q=0 otherwise 2Q^2 is most definitely not equal to 4Q for any other value of Q.
> 
> If anyone else has a problem with us americans, well…
> 
> 4Q!

Well, that's the attitude the world expects to see from us... :-)

John

> On Sep 24, 2015, at 7:11 PM, coco-request at maltedmedia.com wrote:
> 
> > Date: Thu, 24 Sep 2015 11:08:55 -0500
> > From: "camillus1" <camillus.b.58 at gmail.com>
> > To: "Bill Pierce via Coco" <coco at maltedmedia.com>
> > Subject: Re: [Coco] E-mail Netiquette: How to Start a New Thread
> > Message-ID: <66114bc1-298e-43ae-8ae8-9ad62bb43b3a at getmailbird.com>
> > Content-Type: text/plain; charset="utf-8"
> > 
> > My $0.02....
> > 
> > 2Q^2 is not the same as 4Q
> > 
> > 4Q = 4 x Q
> > 
> > 2Q^2 = 2Q x 2Q
> > 
> > If Q would be 2 then   4Q = 4 x 2 = 8
> >                                 2Q^2 = (2 x 2) x (2 x 2) = 4 x 4 = 16
> > 
> > 2Q + 2Q                             = 4Q
> > 
> > Or am I seeing this wrong???
> > 
> > cb
> > On 9/24/2015 8:47:18 AM, Chester Patterson <chester6809 at gmail.com> wrote:
> > The correct answer, of course, said with some degree of vehemence, is "4Q"
> > Say it out loud. It'll hit in a few seconds...
> > Uncle Bill did so love his math giggles.
> 
> 
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-- 
John W. Linville		Someday the world will need a hero, and you
linville at tuxdriver.com			might be all we have.  Be ready.