[Coco] a not very important Drivewire question

[Kip Koon]

Hi Guys!
If anyone is interested, 256 Drive Busses of 256 drives = 65536 drives of a
configuration of 35 tracks SSDD each would require a disk space of
10,569,646,080 bytes or 9.84375GBs if my calculations are correct and that
does not include any NitrOS9 partitions!  Wow!  Can anybody keep track of
that many floppies?  :)  If we use one of Bill Pierce's vhd files as a
starting point, then if one vhd file occupies 132,480KB or 129.375MB, then
129.375MB *256 Drive Busses = 33120MB or 32.34375GB of hard drive space.
Anyone up to the challenge?  :)  

Kip Koon
computerdoc at sc.rr.com
http://www.cocopedia.com/wiki/index.php/Kip_Koon
http://computerpcdoc.com/


-----Original Message-----
From: Coco [mailto:coco-bounces at maltedmedia.com] On Behalf Of Robert Gault
Sent: Thursday, July 17, 2014 8:14 PM
To: CoCoList for Color Computer Enthusiasts
Subject: Re: [Coco] a not very important drivewire question

Robert Hermanek wrote:
> I don't suppose anybody has a text file with the assembler output of 
> HDB-DOS 1.1D DW3 COCO 3, so I could find the address of that #MAXDN-1 
> below and poke a
> 255 in there instead...
>
> On 7/16/2014 9:46 PM, Robert Gault wrote:
>> * Select Device ID number
>> DNUM           jsr       <$9F                Parse over "#"
>> DSET05         jsr       LB70B               Evaluate argument
>>                cmpb      #MAXDN-1            Legal?
>>                bhi       FCERR               No, ?FC ERROR
>
>

There is only one $C1FE (aka CMPB #254) in the hdbdw3cc3.rom and that is at
$1CAA in the file. This ought to be correct as just before that is a $BD
B70B which would be the JSR $B70B.

Robert

PS. I did compile HDBDOS with maxdn=256 and it works for a DW4 slot of 255.

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